Sort:  

I wrote a little python script to do it for me:

l = (0,1,2,3,4,5)
hist = []
def getNext(l):
        return (l[1],l[2],l[3],l[4],l[5],int(str(sum(l))[-1]))

for i in range(100000):
        hist.append(l)
        l = getNext(l)
        print(l)
        if l in hist:
                print("DUPLICATE at {}".format(i))
                break
        if l == (1,3,5,7,9):
                print("FOUND IT")

After 1456 iterations of this loop, we come back to the original 6 terms of the sequence and we still haven't encountered 13579.

I have no good mathematical answer for why this is true though...which I assume there is?

Actually I'm still trying to solve this myself. I really like the code. There could be a sequence of 2x+1 starting with x=0 and going to x=4 that is past 1456 iterations. The way to prove it would be to find a recurring cycle and show that this cannot be part of the cycle. What I'm trying to do right now is see if it has any pattern to it.

That's what I'm saying I did...the code finds a cycle at the 1456th iteration

Loading...