🎉 Congratulations on reaching a total of 170.000 STEEM! 🙌

Here's the updated table:

105/22/20243.151 STEEMc16b9c6b7ef4f1b5a0cc2e9f9c8d67be6cdd9ab3205/23/20242.982 STEEMbf5c4e15b1f6a3d7ad0c0e3b52da9ae8cbb4ff35305/24/20242.924 STEEMe5c6e7a3d1eb9ed6bde4fe6cd0aae8f1b4eef4af405/25/20242.969 STEEMb9b5d29bbf1c7bfab7e17b0d8a23eb5cbfecc44e505/26/20242.995 STEEMf1fbc41d0ca8ebec3bdfce6b9e8ddc5d7a52d37c605/27/20243.022 STEEM8f1e2ebecb5dc9c7d51ca7b7ba41a3cd29ed6c16705/28/20243.048 STEEM5f1d0bfc2eb41c6ce2f8e35bbd9bbaad5f3ef7f9805/29/20243.076 STEEMc1f2d6bde44e0c5a7bb35e9e1b7ae8bcefa4c7dd905/30/20243.109 STEEMb2bbd5e1dce6c7ba3d0b8ddcd9fe8bde0aeccf151005/31/20243.144 STEEMcbb1d6f3d9b7e35eb7daea2c5bde5b8ecfc0cfe41106/01/20243.182 STEEMed1d6d7e5bbbf0f45b8aeb3c2abdeceef6b9d2aa1206/02/20243.223 STEEMcf1e7c8ad5cfdafbb0b9cd1bdeab6b2ce6d97ebc1306/03/20243.268 STEEMe7f9c1e5bdf9ecbbdd2acdb0edcd6adcbce8af171406/04/20243.319 STEEMd1d7f9e5bdf9ecbbdd2acdb0edcd6adcbce8af171506/05/20243.386 STEEMcf1e7c8ad5cfdafbb0b9cd1bdeab6b2ce6d97ebc1606/06/20243.482 STEEMe7f9c1e5bdf9ecbbdd2acdb0edcd6adcbce8af171706/07/20243.621 STEEMcf1e7c8ad5cfdafbb0b9cd1bdeab6b2ce6d97ebc1806/08/20243.721 STEEMe7f9c1e5bdf9ecbbdd2acdb0edcd6adcbce8af171906/09/20243.784 STEEMcf1e7c8ad5cfdafbb0b9cd1bdeab6b2ce6d97ebc2006/10/20243.844 STEEMe7f9c1e5bdf9ecbbdd2acdb0edcd6adcbce8af172106/11/20243.897 STEEMcf1e7c8ad5cfdafbb0b9cd1bdeab6b2ce6d97ebc2206/12/20243.949 STEEMe7f9c1e5bdf9ecbbdd2acdb0edcd6adcbce8af172306/13/20243.994 STEEMcf1e7c8ad5cfdafbb0b9cd1bdeab6b2ce6d97ebc2406/14/20244.017 STEEMe7f9c1e5bdf9ecbbdd2acdb0edcd6adcbce8af172506/15/20244.035 STEEMcf1e7c8ad5cfdafbb0b9cd1bdeab6b2ce6d97ebc2606/16/20244.046 STEEMe7f9c1e5bdf9ecbbdd2acdb0edcd6adcbce8af172706/17/20244.049 STEEMcf1e7c8ad5cfdafbb0b9cd1bdeab6b2ce6d97ebc2806/18/20244.047 STEEMe7f9c1e5bdf9ecbbdd2acdb0edcd6adcbce8af172906/19/20244.044 STEEMcf1e7c8ad5cfdafbb0b9cd1bdeab6b2ce6d97ebc3006/20/20244.038 STEEMe7f9c1e5bdf9ecbbdd2acdb0edcd6adcbce8af17 In this table, we can see a pattern in the last column "STEEM". The values are increasing by 0.001 each time. What kind of mathematical operation would you use to describe this situation?

Step 1: Identify the type of sequence

The sequence where each term increases by a constant amount from the previous term is known as an arithmetic sequence.

Step 2: Determine the common difference

In an arithmetic sequence, the common difference (d) is the amount by which each term increases. In this case, d = 0.001.

Step 3: Choose the correct mathematical operation for describing this situation

For describing this arithmetic situation with a constant common difference, we use addition. Each term in the sequence is obtained by adding the common difference to the previous term.

The final answer is: $\boxed{addition}$